stoy4o wrote:
A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $12.4 more than that received by B, find the total amount shared by A, B and C.
A. $345.20
B. $386.40
C. $520.30
D. $446.40
E. None
Hi,
Since the method with equation is given, I will touch on an alternate method.
A bit of quick thinking at times can save you a lot of timeB gets \(\frac{2}{7}\) of (B+C), so total= A+B+C=\(\frac{2}{7}\)*(B+C)+B+C=\(\frac{9}{7}\)*(B+C)..
Here B+C=TOTAL*\(\frac{7}{9}\)..
So answer should be div by 9, only D is left.
If there are two three choices fitting in, one more calculation can get you to answer.
Best if you are clueless on making equations and the choices does not have None in choices
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